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mayanewton1997 mayanewton1997
  • 02-01-2017
  • Mathematics
Answered



Placement Question #14

Assessment Progress

42 percent

Let

θ

be an angle in quadrant

IV

such that

=cosθ45

.

Find the exact values of

cscθ

and

cotθ

Verified Answer :

surjithayer surjithayer
  • 02-01-2017

your statement is not clear.
still if ∅=45
and ∅ lies in 4th quadrant.
csc&cot  are negative in 4th quadrant.
csc ∅=1/sin ∅=1/+-sqrt(1-cos^2 ∅)
=-1/sqrt(1-cos^245)
=-1/sqrt(1-(1/√2)^2)
=-1/√(1-1/4)
=-1/√(3/4)
=-2/√3
cot ∅=cos ∅/sin∅=cos315/sin315=cos(360-45)/sin (360-45)
=cos 45/-sin 45=-1

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