Data:
m (mass) = ?
MM (Molar Mass) of H2O2
H = 21 = 2u
O = 216 = 32u
----------------------
MM H2O2 = 34 g/mol
M (molarity) = ?
V = 1500mL → V = 1,5 L
n (molar solution) = 1,33 mol
\(M = \frac{n}{V} = \frac{1,33}{1,5}\)
\(M\approx0,8mol/L\)
Soon:
\(M = \frac{m}{MM*V}\)
\(0,8 = \frac{m}{34*1,5}\)
\(0,8 = \frac{m}{51}\)
\(m = 0,8*51\)
\(\boxed{m = 40,8g}\)
