Answer:
\((x+3)^2+(y-4)^2=9\)
Step-by-step explanation:
We are given a circle which is centered at the point (-3,4) and has a radius of length 3.
We have to find the equation of the circle.
The equation of circle centered at (a,b) and radius r is:
\((x-a)^2+(y-b)^2=r^2\)
Here a=-3 , b=4 and r=3
Hence, equation of circle is:
\((x+3)^2+(y-4)^2=3^2\)
\((x+3)^2+(y-4)^2=9\)
