Verified Answer :

\(\frac{ \sqrt{x} +3}{ \sqrt{x} }\)=1+\(\frac{3}{ \sqrt{x} }\)

remember
dy/dx(f(x)/g(x))=((f'(x)g(x)-g'(x)f(x))/(g(x)^2)

dy/dx(1+\(\frac{3}{ \sqrt{x} }\))=0+(0-(3/(2\(\sqrt{x}\))))/x=(-3/(2\(\sqrt{x}\)))/x=-3/(2\(x\sqrt{x}\))