Answer: It will become,
\(49t^6-4k^4=(7t^3-2k^4)(7t^3+2k^4)\)
Step-by-step explanation:
Since we have given that
\(49t^6-4k^8\)
We need to factorise the above expression:
\(49t^6-4k^8\\\\=(7^2(t^2)^3-2^2(k^2)^4\\\\=(7t^3)^2-(2k^4)^2\)
So, we can apply the identity :
\(a^2-b^2=(a+b)(a-b)\)
Here,
\(a=7t^3\\\\b=2k^4\)
so, it will become,
\(49t^6-4k^4=(7t^3-2k^4)(7t^3+2k^4)\)
