4x+2y=34;10x-4y=-5I Need Help
\(\left \{ {{4x+2y=34\ \ | *2} \atop {10x-4y=-5}} \right. \\\\ \left \{ {{8x+4y=68} \atop {10x-4y=-5}} \right. \\+-----\\addition\ method\\\\ 18x=63\ \ \ | divide\ by\ 18\\\\ x=3.5\\\\ 2y=34-4x\\\\y=\frac{34-4x}{2}=\frac{34-4*3.5}{2}=\frac{34-14}{2}=\frac{20}{2}=10\\\\ Solution:\\ \left \{ {{y=10} \atop {x=3.5}} \right.\)
