Christine baked a pumpkin pie. she ate 1/6 of the pie. her brother ate 1/3 of it and gave the leftovers to his friends. what fraction of the pie did he give to his friends?
The fraction of the pie given to his friend is \(\frac{1}{2}\)
The leftover given to his friends will be determined adding the portion Christine and her brother ate which are \(\frac{1}{6}\) and \(\frac{1}{3}\) respectively, then subtracted from the whole portion.
= \(\frac{1}{6}\) + \(\frac{1}{3}\) (The lowest common denominator of 6 and 3 = 6)
= (1 x 1) + (2 x 1) /6
= (1) + (2) / 6
= 1 + 2 / 6
= \(\frac{3}{6}\)
Thus, total portion of the pie eaten by Christine and her brother = \(\frac{3}{6}\) . Also the fraction of the whole portion of the pie = \(\frac{6}{6}\)
Determining the portion given to the friend =
Subtracting \(\frac{6}{6}\) – \(\frac{3}{6}\)
= \(\frac{6}{6}\) – \(\frac{3}{6}\) (The lowest common denominator of 6 and 6 = 6)
= (1 x 6) – (1 x 3) / 6
= (6) – (3) / 6
= 6 – 3 / 6
= \(\frac{3}{6}\)
= \(\frac{1}{2}\) (further broken down to this)
Therefore the fraction given to the friend is \(\frac{1}{2}\).
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