- Simplify the inequality \(8 > 2k - 3\) by adding \(3\) to both sides: \(11 > 2k\).
- Divide by \(2\) to find the range: \(k < 5.5\).
- Check the candidate values: only \(k = 2\) is less than \(5.5\).
- The correct option is \(\boxed{c}\).
Explanation
- Analyzing the Problem
We are given the inequality \(8 > 2k - 3\) and four candidate values for \(k\): \(k=8\), \(k=12\), \(k=2\), and \(k=9\). Our objective is to identify which of these values makes the inequality true. The inequality is a linear inequality, which we can solve by isolating the variable \(k\).
- Solving the Inequality
To solve the inequality \(8 > 2k - 3\) for \(k\), we follow algebraic steps to isolate the variable:
- Add \(3\) to both sides of the inequality:
\[8 + 3 > 2k - 3 + 3\]
\[11 > 2k\]
- Divide both sides by \(2\):
\[\frac{11}{2} > k\]
\[5.5 > k\]
Thus, the inequality is satisfied if and only if \(k\) is less than \(5.5\).
- Evaluating Candidates and Conclusion
Now, we test each of the provided candidate values against the condition \(k < 5.5\):
- For \(k = 8\): \(8 < 5.5\) is false.
- For \(k = 12\): \(12 < 5.5\) is false.
- For \(k = 2\): \(2 < 5.5\) is true.
- For \(k = 9\): \(9 < 5.5\) is false.
Only \(k = 2\) satisfies the condition. Therefore, option (c) is the correct answer.
Examples
Understanding and solving linear inequalities is essential in real-life resource management and logistics. For example, if you have a budget of \$800 for a project and each unit of a component costs \$200, but there's a flat delivery fee of \$300, you could model the number of units \(k\) you can afford with the inequality \(200k + 300 \leq 800\). Solving such inequalities helps in planning and decision-making by setting clear boundaries for what is feasible.