Verified Answer :

(x-2)(x+2) = x(x+2) - 2(x+2)

(x-2)(x+2) = xx + x2 - 2x - 22

(x-2)(x+2) = x^2 + 2x - 2x - 4

(x-2)(x+2) = x^2 - 4

That's the long way to do it. You can use the difference of squares formula as a shortcut

(a-b)*(a+b) = a^2 - b^2

(x-2)(x+2) = x^2 - 2^2

(x-2)(x+2) = x^2 - 4

either way, the final answer is x^2 - 4

BobR9

(X-2)(x+2)
So use "f.o.i.l" meaning you multiply each first term, the outside terms, the inside terms and last terms, and then add. You'd get x^2-4 in this example