we have
\(x^{2} =-13x-4\\ x^{2} +13x+4=0\)
we know /that
Since you can not get the roots by easily factoring the equation, you have to use the quadratic equation.
The quadratic equation is
\(x=(-b + /-\sqrt{(b^{2}-4ac)} )/(2a)\)
in this problem
\(a=1\\ b=13\\ c=4\)
substitute in the equation
\(x=(-13 + /-\sqrt{(13^{2}-4*1*4)} )/(2)\)
\(x=(-13 + /-\sqrt{(153)} )/(2)\)
the roots are
\(x1=(-13 + \sqrt{(153)} )/(2)\)
\(x2=(-13 -\sqrt{(153)} )/(2)\)
\(x1=(- \frac{13}{2} )+( \frac{3}{2} )* \sqrt{17}\)
\(x2=(- \frac{13}{2} )-( \frac{3}{2} )* \sqrt{17}\)
