What is the sum of the two digit multiples of 11?
\(S = \frac{1}{2}n(a + l)\)\(a = 11\)\(l = 99\)\(n = 9\)\(S = \frac{1}{2}9(11 + 99)\)\(S = \frac{1}{2}9(110)\)\(S = \frac{990}{2}\)\(S = 495\)
11+22+33+44+55+66+77+88+9933+77+121+165+99110+286+99396+99495