3x + 4y= 16 solve for y
3x + 4y = 16- 3x -3x 4y = -3x + 16 (divide each side by 4) \(\frac{4y}{4} = \frac{-3x+16}{4}\) y = -3/4x + 16/4 The answer is \(y =- \frac{3}{4}x +4\)