x^2 - 4x + 3 how do I factor the expression completely
bx must be the sum of the numbers in the bracket and c must be the product. So we need to choose 2 numbers that multiply to make 3 and add to make -4.A negative x negative = positive so-3*-1=3-3-1=-4Therefore:(x-3)(x-1)
\(x^2 - 4x + 3=\\ x^2-x-3x+3=\\ x(x-1)-3(x-1)=\\ (x-3)(x-1)\)
