what is the [oh−] of a solution with ph 5.75
[ H₃O⁺] = 10 ^- pH
[ H₃O⁺] = 10 ^ (- 5.75 )
[H₃O⁺] = 1.778x10⁻⁶ M
Kw = [ H₃O⁺] x [ OH⁻]
1x10⁻¹⁴ = 1.778x10⁻⁶ x [OH⁻]
[OH⁻] = 1x10⁻¹⁴ / 1.778x10⁻⁶
[OH⁻] = 5.62x10⁻⁹ M
hope this helps!
Explanation:
pH means potential of hydrogen and it is defined as the measure of concentration of hydrogen ions in a solution.
Mathematically, pH = \(-log[H^{+}]\)
Also, it is known that relationship between pH and pOH is as follows.
pH + pOH = 14
or pOH = 14 - pH
Therefore, putting the value of pH in the above relationship as follows.
pOH = 14 - pH
= 14 - 5.75
= 8.25
Hence, pOH = \(-log [OH^{-}]\)
or, \([OH^{-}]\) = antilog (-8.25)
= \(5.62 \times 10^{-9}\)
Thus, we can conclude that the [oh−] of a solution with ph 5.75 is \(5.62 \times 10^{-9}\).