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Colby and Jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the number of bacteria doubles every 2 hours. Jaquan has a different type of bacteria that doubles every 3 hours. How many bacteria should Jaquan start with so that they have the same amount at the end of the day?


BTW I dont want bacteria formula

Verified Answer :

I assume here that the day here is the 24 period. This means that if the bacteria doubles every 2 hours, this will happen 12 times (24/2=12).

So Colby will have 50222222222222=50444444=20044444=8004444=3200444=204800 bacteria.

if the bacteria doubles every 3 hours, this will happen 8 times (24/3=8).

So Jaquan will have

x22222222=x4444=x1616=x 256

So if we want so have the same amount:

204800=x256
x=800

So he needs to start with 800.




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