what is 2x^2y^3/-8xy^4
\(\dfrac{2x^2y^3}{-8xy^4}=-\dfrac{2}{8}\cdot\dfrac{x^2}{x}\cdot\dfrac{y^3}{y^4}=-\dfrac{1}{4}\cdot\dfrac{x}{1}\cdot\dfrac{1}{y}=\boxed{-\frac{x}{4y}}\)
