Verified Answer :

LammettHash

\(x^2-6x+7=x^2-6x+9-2=(x-3)^2-2\)

is a parabola with its vertex at \((3,-2)\), which means the minimum value is \(-2\).

dexteright02

\(x^{2} - 6 + 7 = 0\)
a = 1; b = - 6, c = 7
Δ = b² - 4.a.c
Δ = (-6)² - 4.1.7
Δ = 36 - 28
Δ = 8

Calculate the minimum value:

\(Y_{v} = \frac{-\Delta}{4a}\)

\(Y_{v} = \frac{-8}{4*1}\)
\(Y_{v} = \frac{-8}{4}\)
\(\boxed{Y_{v} = -2}\)

Answer:
\(\boxed{\textcircled{ A } = -2}\)

Follow the attachment (graphic):

View image dexteright02

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