Verified Answer :

Willchemistry

Molar mass N2 = 14 x 2 => 28.0 g/mol

1 mole N2 ------------- 28.0 g
? moles N2 ----------- 550 g

550 x 1 / 28.0 => 19.64 moles of N2

Answer:

Moles of nitrogen present in the cylinder = 19.64 mol

Explanation:

Given:

Weight of \(N_2\) = 550 g

Formula for the calculation of moles is:

\(mol=\frac{Weight\ in\ g}{Molecular\ mass}\)

Molecular mass of \(N_2\) = 28 g/mol

\(mol=\frac{550\ g}{28\ g/mol} = 19.64\ mol\)

Moles of nitrogen present in the cylinder = 19.64 mol