25 POINTS!!!!!!

The function f(x) = 467(5)x represents the growth of a ladybug population every year in a wooded area. Adrianne wants to manipulate the formula to an equivalent form that calculates every 3 months, not every year. Which function is correct for Adrianne's purposes?

Af(x) = 67(5)x
Bf(x) = 467(512)the x over 12 power
Cf(x) = 467(5 to the one fourth power)4x
Df(x) = 4672(5)x

Verified Answer :

Your anwer is C)f(x) = 467(5 to the one fourth power)4x

Answer: C. \(f(x)=467(5)^{\frac{1}{4}x}\)

Step-by-step explanation:

Given: The function \(f(x)=467(5)^x\) represents the growth of a ladybug population every year in a wooded area.

If Adrianne wants to manipulate the formula to an equivalent form that calculates every 3 months, not every year.

Then, the time changes from 1 year to 3 months.

Since, 1 year = 12 months

And 1 month = \(\frac{1}{12}\) year

So, 3 months = \(\frac{3}{12}=\frac{1}{4}\) year

So, the required function would look like :_

\(f(x)=467(5)^{\frac{1}{4}x}\)

Hence, C is the right answer.