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Greenrune113 Greenrune113
  • 19-08-2016
  • Mathematics
Answered

Find all real values of x such that f (x) = 0.

\(f(x) = \frac{-6x - 9}{2}\)

Verified Answer :

TSO
TSO TSO
  • 20-08-2016

Plug in f(x) = 0

0 = (-6x - 9)/2

Multiply 2 on both sides

0 = -6x - 9

Add 9 on both sides

9 = -6x

Divide -6 on both sides

x = 9/-6 = -3/2

When x = -3/2, f(x) = 0

Answer Link
Anonymous Anonymous
  • 20-08-2016

Plug in f(x) = 0 to solve 

\(f(x) = \frac{-6x-9}{2}\)

\(0 = (-6x - 9)/2\)

\(0 = -6x - 9\)

\(9 = -6x\)

\(x = 9/-6 = -3/2\)

\(x = -3/2, f(x) = 0\)

Answer Link

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