Which of the following inequalities matches the graph? graph of an inequality with a solid line through the points (0, −2) and (2, 1)with shading above the line
3x − 2y greater than or equal to 4
3x − 4y less than or equal to 2
3x − 2y less than or equal to 4
The correct inequality is not listed.

1) Equation of the line

Slope, m = [-2 -1]/[0 - 2] = -3 / -2 = 3/2
y-intercept, b = -2

y = 3x/2 - 2

2) Inequality
The points over the line have y-coordinate greaetr than the value of the line, then

y ≥ 3x/2 - 2

2y ≥ 3x - 4

3x - 2y ≤ 4

3) Answer: 3x - 2y less than or equal to 4.

Answer Link

DelcieRiveria DelcieRiveria · Answer 2 · 2019-01-03T06:18:16-05:00

Answer:

The correct option is 3.

Step-by-step explanation:

It is given that graph of an inequality with a solid line through the points (0, −2) and (2, 1) with shading above the line.

The equation of solid line is

\(y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\)

\(y+2=\frac{1+2}{2-0}(x-0)\)

\(y+2=\frac{3}{2}x\)

The y-intercept of the line is -2 and the shaded region is shading above the line. So, (0,0) must be lies in the shaded region.

Check the related equation by point (0,0).

\(0+2=\frac{3}{2}(0)\)

\(2=0\)

The statement is true if and only if the sign is greater than or equal instead of equal.

The required inequality is

\(y+2\geq \frac{3}{2}x\)

Multiply both sides by 2.

\(2y+4\geq 3x\)

\(4\geq 3x-2y\)

\(3x-2y\leq 4\)

Therefore option 3 is correct.