A triangular box of sticky notes is shown. Find the volume of the box. 3.5 5.2 6
Volume = base width height = 3.5 5.2 6 =
109.2 cubed units
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The area of a triangle is half the product of the base of the triangle and the height of the triangle. The volume of the triangular box is 54.6 in³.
The area of a right-angle triangle is half the product of the base of the triangle and the height of the triangle.
\(\rm{ Area \triangle = \dfrac{1}{2} \times base \times height\\\)
As it is given that the length of the altitude of the triangle and the base of the triangle is 3.5 inches and 5.2 inches respectively. While the height of the box is 6 inches. Therefore, the volume of the triangular box can be written as,
\(\rm \text{Volume of the triangular box} = \text{(Area of triangle)} \times Height\)
\(=(\dfrac 12 \times 3.5 \times 5.2) \times 6\\\\= 54.6\rm\ in^3\)
Thus, the volume of the triangular box is 54.6 in³.
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