Consider $f(x)=\sqrt{x^2-1}$ and $g(x)=\sqrt{x^2+1}$. What value(s) of $x$ would make $f(g(x))$ and $g(f(x))$ commutative?

A$x \geq 1$ or $x \leq -1$

B$-1 \leq x \leq 1$

Cany value of $x$

Dno value of $x$