Answer:
Take 0.57 L of 18.5 M HCl solution and make its volume upto 3 L by adding it 2.43 L of water.
Explanation:
\(M_1V_1=M_2V_2\) (Dilution)
where,
\(M_1\text{ and }V_1\) are the , molarity and volume of acid which is formed after dilution
\(,M_2\text{ and }V_2\) are the , molarity and volume of acid which is diluted
We are given:
\(M_1=3.5 M\\V_1=3.0 L\\M_2=18.5 M\\V_2=?\)
Putting values in above equation, we get:
\(3.5 M\times 3.0 L=18.5 M\times V_2\\\\V_2=0.57 L\)
Volume of 18.5 M HCl required = 0.57 L
Volume to be added in 0.57 L of 18.5 M HCl so that we have 3.5 M of HCl solution:
\(V_1-V_2=3.0 L - 0.57 L = 2.43 L\)
Take 0.57 L of 18.5 M HCl solution and make its volume upto 3 L by adding it 2.43 L of water.
