Solve for T in a/2=ae^-9.548t
\(\dfrac{a}{2}=ae^{-9.548t}\\ \dfrac{1}{2}=e^{-9.548t}\\ -9.548t=\ln \dfrac{1}{2}\\ t=-\dfrac{\ln\dfrac{1}{2}}{9.548}\\ t=\dfrac{\ln 2}{9.548}\)
