PLEASEEE HELP. Solve x^3-7x^2+6x-42=0
factor by groupingx^2(x-7) + 6(x-7) = 0 [took x^2 out of the first two and a 6 out of the last two](x-7)(x^2+6) = 0 [moved (x-7) out to the front]x = -i sqrt(6) , i sqrt(6) , 7only one real solution of x = 7
\(x^{3} -7 x^{2} +6x-42=0\)\((x-7)\) is a factor since it is a factor of -42 and 7 is a solution for f(x) to equal 0.\((x-7)(a x^{2} +bx+c)=0\)\((x-7)( x^{2} +bx+6)=0\)\(-7 x^{2} +b x^{2} =-7 x^{2}\)\(-7+b=-7\)\(b=0\)\((x-7)( x^{2} +6)=0\)\(x-7=0\)\(x^{2} +6=0\)\(x=7\) (only solution because you can't square root (-6))
