Verified Answer :

\(_n{P}_r = \frac{n!}{(n - r)!}\)
\(_9P_3 = \frac{9!}{(9 - 3)!}\)
\(_9P_3 = \frac{9!}{6!}\)
\(_9P_3 = \frac{9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1}{6 * 5 * 4 * 3 * 2* 1}\)
\(_9P_3 = 9 * 8 * 7\)
\(_9P_3 = 72 * 7\)
\(_9P_3 = 504\)