If an object is projected upward with an initial velocity of 126 ft per sec, its height h after t seconds is h= -16^2+126t. Find the height of the object after 5 seconds
All you would have to do is plug in 5 for t since that is the time; then you would see that the height of the object after 5 seconds is 886 ft. Hope this helped!
Answer:
230 ft is the height of the object after 5 seconds
Step-by-step explanation:
As per the statement:
If an object is projected upward with an initial velocity of 126 ft per sec.
The height h after t seconds is given by:
\(h(t) = -16t^2+126t\)
We have to find the height of the object after 5 seconds.
At t = 5 seconds
\(h(5) = -16(5)^2+126(5)\)
⇒\(h(5) = -16 \cdot 25+630\)
⇒\(h(5) = -400+630\)
Simplify:
h(5) = 230 ft
Therefore, the height of the object after 5 seconds is, 230 ft