Verified Answer :

\(a^{-n}=\left(\dfrac{1}{a}\right)^n\\-------------------\\\left(\dfrac{1}{3}\right)^{-5}=\left(\dfrac{3}{1}\right)^5=3^5=3\cdot3\cdot3\cdot3\cdot3=\huge\boxed{243}\leftarrow \boxed{a}\)

\(If\ the\ expression\ is\ \dfrac{1}{3^{-5}}\ therefore\ is\ the\ same\ \dfrac{1}{\dfrac{1}{3^5}}=3^5=\huge\boxed{243}\)

TSO

\(a^{-b}=\frac {1}{a^b}\\\\ \frac {1}{a^{-b}}=a^b\)

So,
\(\frac {1}{3^{-5}}=3^5= 3 \times 3 \times 3 \ times 3 \times 3 = 243\)

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