A savings account compounds interest, at a rate of 17%, once a year. John puts $1,000 in the account as the principal. How can John set up a function to track the amount of money he has?
The amount after t years be can be found by using the following function of t:
\(f(t)=1000(1+0.17)^{t}\)
Answer:
The function to track the amount is \(y = a (1+r)^{t}\) and the value of amount is $1170 .
Step-by-step explanation:
As given
A savings account compounds interest, at a rate of 17%, once a year. John puts $1,000 in the account as the principal.
The function is defined as
\(y = a (1+r)^{t}\)
Where a is the principle value , r is the rate of interest in the decimal form and t is the time in years .
P = $1000
17% is written in the decimal form .
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= 0.17
r = 0.17
t = 1 years
Put all the values in the function
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y = $1170
Therefore the function to track the amount is \(y = a (1+r)^{t}\) and the value of amount is $1170 .