what is the additive inverse of the complex number 9 – 4i?
The additive inverse is were if you add the number an its opposite it become zero, so therefore this would show you that the opposite of this number is -9+4i , to help remember what a additive inverse is just think of how a inverse is like a opposite an remember that the inverse plus your number will equal zero.
I hope this helps.
Answer: The additive inverse of the given complex number is \(-9+4i.\)
Step-by-step explanation: We are given to find the additive inverse of the following complex number :
\(z=9-4i.\)
We know that
the complex number z' is the additive inverse of a complex number z, if
\(z+z'=0.\)
So, let z' be the additive inverse of the given complex number z.
Then, we must have
\(z+z'=0\\\\\Rightarrow (9-4i)+z'=0\\\\\Rightarrow z'=0-(9-4i)\\\\\Rightarrow z'=-9+4i.\)
Thus, the additive inverse of the given complex number is \(-9+4i.\)