Answer:
\(-16\frac{5}{7}\)
Step-by-step explanation:
we know that
Two numbers are additive inverse if their sum is equal to zero
Let
x-------> the additive inverse of \(16\frac{5}{7}\)
so
\(x+16\frac{5}{7}=0\)
solve for x
Subtract \(16\frac{5}{7}\) both sides
\(x+16\frac{5}{7}-16\frac{5}{7}=-16\frac{5}{7}\)
\(x=-16\frac{5}{7}\) -------> additive inverse