Answer:
Use conversion:
\(1 joule = 1 kg m^2/s^2\)
As per the given statement:
Mass of the skier(m) = 60 kg
height of the slope(h) = 10m/s
Speed(v) = 10m/s
By conservation of Energy states the law of conservation of energy states that the total energy of an isolated system remains constant.
\(P.E - K.E + E = 0\)
P.E(Potential Energy) = mgh
K.E(Kinetic Energy)=\(\frac{1}{2}mv^2\)
E represents the energy lose due to friction.
then;
\(mgh -\frac{1}{2}mv^2 + E = 0\)
Substitute the given values;
Use \(g = 9.8 m/s^2\)
then;
\((60)(9.8)(10) -\frac{1}{2}(60)(10)^2 + E = 0\)
Simplify:
\(5880-3000+E = 0\)
\(2880+E =0\)
or
\(E = -2880 kgm^2/s^2\)
Therefore, the energy does she lose to friction is 2880 joule
