To form the quadratic equation, form II equations;
(x-(\(\frac{-5}{4}\))(x-8)=0
(\(x+\frac{5}{4} )\)(x-8)=0
Open the brackets;
x(x-8)+\(\frac{5}{4}\)(x-8)=0
\(x^{2} -8x+ \frac{5}{4} x-10=0\)
\(x^{2} - \frac{32}{4} x- \frac{5}{4} x-10=0\)
\(x^{2} - \frac{27}{4} x-10=0\)
This can be simplified to;
\(4x^{2} -27x-40=0\)