Answer:
out of the two functions g(x) attains the minimum y-value.
Step-by-step explanation:
We are given the function \(f(x)=x^4-2\) and \(g(x)=3x^3+2\).
now we have two check out of the two functions above which has the smallest minimum y-value.
Clearly from the graph attached to the solution of f(x) and g(x), we could see that for f(x) the minimum value of y is -2 while for g(x) the value of y goes on decreasing as x goes to minus infinity.
Hence g(x) attains the minimum value for y.
