Verified Answer :

nobillionaireNobley

The vertex form of a quadratic function is given by f(x) = (x - h)^2 + k, where (h, k) is the vertex of the function. Hence, for the given function, vertex = (2, 4)
Domain is all real numbers and range is {f(x) : f(x) >= 4}

calculista

we have

\(f(x) = (x - 2)^{2} + 4\)

This is a vertical parabola open up, so the vertex is a minimum

we know that

The vertex form of a vertical parabola function is given by the formula

\(f(x) = (x - h)^2 + k\)

where

(h, k)---------->  is the vertex of the function

In this problem

the vertex is the point (2,4)

The domain is all real numbers----------> interval (-∞,∞)

The range is the interval------------> [4, ∞)

using a graph tool

see the attached figure

View image calculista

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