$6,000 dollars is invested in two different accounts earning 3% and 5% interest. at the end of one year, the two accounts earned $220 in interest. how much money was invested at 5%?
the 2 values invested are x and 6000-x
I=PRT
interest=principal times rate times time
time is 1 year so t=1
r=0.03 ad 0.05
we want to find 5% so x is wha we solve for
the interests are
0.03(6000-x) and 0.05x
they add to 220
220=0.03(6000-x)+0.05x
220=180-0.3x+0.05x
220=180+0.02x
minus 180 both sides
40=0.02x
divide both sides by 0.02
2000=x
$2000 was invested at 5%
Answer-
$2000 were invested at 5%
Solution-
Let x amount of money was invested at 5% and (6000-x) amount was invested as 3%
We know that,
@@MATH_TOKEN_0@@
Putting the values,
@@MATH_TOKEN_1@@
@@MATH_TOKEN_2@@
And
@@MATH_TOKEN_3@@
@@MATH_TOKEN_4@@
According to the question,
@@MATH_TOKEN_5@@
@@MATH_TOKEN_6@@
@@MATH_TOKEN_7@@
@@MATH_TOKEN_8@@
@@MATH_TOKEN_9@@
@@MATH_TOKEN_10@@
@@MATH_TOKEN_11@@
Therefore, $2000 were invested at 5%