a population of 430 animals decreases at an annual rate of 21% find the multiplier for the rate of exponential decay
If the population of the animals decreases by about 21% of its current population, it means that the population next year is only 1 - 0.21 or 0.79 of its current population. Thus, the multiplier for the rate of the exponential decay is 0.79.
Answer:
0.79
Step-by-step explanation:
We have been given that a population of 430 animals decreases at an annual rate of 21%. We are asked to find the multiplier for the rate of exponential decay.
We know that an exponential decay function is in form \(y=a\cdot (1-r)^x\), where,
a = Initial value,
r = Decay rate in decimal form.
Let us convert 21% in decimal form as:
\(21\%=\frac{21}{100}=0.21\)
Upon substituting our given values, we will get:
\(y=430\cdot (1-0.21)^x\)
\(y=430\cdot (0.79)^x\)
Therefore, the multiplier for the rate of exponential decay is 0.79.