Answer: The product would be \(d^{j+k}\)
Step-by-step explanation:
Since we have given that
\(d^j.d^k\)
We need to find the product.
As we know that
\(a^m\times a^n=a^{m+n}\)
So, we will use the above exponential law and it becomes,
\(d^j.d^k=d^{j+k}\)
Hence, the product would be \(d^{j+k}\)
