Answer: 55.73 kPa
Explanation:
Using ideal gas law :
\(PV=nRT\)
\(P=\frac{nRT}{V}\)
P = pressure of the gas=?
V = volume of the gas = 500 ml = 0.5L
T = temperature of the gas =\(265^0C=(265+273)K=538K\)
n = number of moles of the gas=\(6.25\times 10^{-3}\)
R = gas constant = 0.0821 Latm/moleK
\(P=\frac{6.25\times 10^{-3}\times 0.0821\times 538K}{0.5}=0.55atm=55.73kPa\)
(1 atm =101.325kPa)
