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Using the polynomials Q = 3x 2 + 5x - 2, R = 2 - x 2, and S = 2x + 5, perform the indicated operation: Q - [R + S]

Verified Answer :

LeviKS

(3x^2+5x-2)- ((2-x^2+2x+5))
(3x^2+5x-2)- ((7-x^2+2x))
Since no more can be added or broken down
3x^2+5x-2 - 7-x^2+2x
2x^2+7x-9

Answer:

\(4x^2+3x-9\)

Step-by-step explanation:

Given the polynomials:

\(Q = 3x^2+5x-2\)

\(R = 2-x^2\)

\(S = 2x+5\)

We have to  perform the indicated operation Q - [R + S]

\(Q - [R + S] = 3x^2+5x-2-[2-x^2+2x+5]\)

⇒\(Q - [R + S] = 3x^2+5x-2-2+x^2-2x-5\)

Combine like terms;

⇒\(Q - [R + S] = 4x^2+3x-9\)

Therefore, Q - [R + S] is, \(4x^2+3x-9\)

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