A series circuit contains two devices, one with a resistance of 10 ohms and one with a resistance of 4 ohms. If the generator supplies a voltage of 42 V, what is the magnitude of the current?
-- The net effective resistance of 10-ohms and 4-ohms
in series is 14 ohms.
-- The current in the series loop is I = E/R = 42V/14-ohms = 3 amperes.
Total resistance = 10 + 4 = 14 ohms = 14Ω
Current = V/R
Current I = 42V / 14Ω = 3 Amperes.