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Answered

The total energy of a 0.050 kg object travelling at 0.70 c is

A2.10 × 107 J

B3.06 × 107 J

C2.46 × 1015 J

D6.30 × 1015 J

E8.82 × 1015 J

Verified Answer :

olemakpadu

Would presume the energy as kinetic energy.

E = (1/2)mv²

But m = 0.05kg, velocity here = 0.70c, where c is the speed of light ≈ 3 10⁸ m/s

Ke =  (1/2)mv² = 0.50.05(0.73 10⁸)² = 1.1025 10¹⁵ Joules


There is no exact match from the options.

Answer:

6.33x10^15

Explanation:

Im sure its too late but this might help someone in the future

the right formula to use is

Etotal=(mc^2)/sqr(1-v^2/c^2)

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