Answered

the tables represent two linear functions in a system


table one

x -6, -3, 0, 3

y= -22, -10, 2, 14


table 2

x = -6, -3, 0, 3

y= -30, -21, -12, -3

what is the solution to this system?

A[-13/3 , -25]
B[-14/3, -54]
C(-13, 50)
D(-14, 54)

Verified Answer :

Kalahira

Answer: D. (-14, -54)

 WORKINGS

 According to Table 1: y = 4x + 2 … (Equation I)

According to Table 2: y = 3x – 12 … (Equation II)

 Substitute the value of y in equation I (4x + 2) for y in Equation II to solve for x

y = 3x – 12

4x + 2 = 3x – 12

4x – 3x = -12 – 2

x = -14

 Substitute -14 for x in Equation I to solve for y

y = 4x + 2

y = 4(-14) + 2

y = -56 + 2

y = -54

 Therefore, x= -14; y = -54

Answer:

D

Step-by-step explanation:

edg 21

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