Verified Answer :

nobillionaireNobley

distance between two parallel lines is given by \(\frac{|b_2 - b_1|}{ \sqrt{ m^{2} +1} } = \frac{|-1 - 4|}{ \sqrt{ 4^{2} +1} } = \frac{|-5|}{ \sqrt{ 16 +1} } = \frac{5}{ \sqrt{17} } =1.21\)

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