K1racruztee7kkf
Answered

Adam, Beth, and Carly walked a total of 10 miles collectively. Beth walked twice as far as Adam, and she walked a half a mile further than Carly. If a = number of miles Adam walks, b = number of miles Beth walks, and c = number of miles Carly walks, which equation is NOT true for this situation?

Ab = 2a
Bb = c + 0.5
C3a + c = 10
Da + 2c = 10.5

Verified Answer :

Ckaranja
Da+2c=10.5

Since b=c+\(\frac{1}{2}\)
a+b+c=10
a+(c+1/2)+c=10
a+2c+1/2=10
a+2c=9.5

Answer: Option 'D' is not correct.

Step-by-step explanation:

Since we have given that

Total distance walked by Adam , Beth, and Carly = 10 miles

Let number of miles Adam walks be a

Let number of miles Beth walks be b

Let number of miles Carly walks be c

According to question,

Beth walked twice as far as Adam

So, the equation will be

\(b=2a\)

Thus, Option 'A' is satisfied.

Now, Beth walked a half a mile further than Carly.

So, the equation will be

\(b=c+0.5\)

Thus, Option 'B' is correct.

Now, we substitute the first equation, then we get

\(a+b+c=10\\a+2a+c=10\\3a+c=10\)

Thus, Option 'C' is correct.

The only incorrect equation is Option 'D' .


Related Questions