Verified Answer :

Answer: \(10x^2-y^2+3xy+6x+3y\)

Step-by-step explanation:

Given expressions are 2x+ y and 5x -y +3

Product of 2x+y and 5x-y+3 is

\((2x+y)\times (5x-y+3) = 2x\times (5x-y+3) + y\times (5x-y+3)\) ( by applying distributive property under multiplication over addition)

⇒\((2x+y)\times (5x-y+3) = 10x^2-2xy+6x+5xy-y^2+3y\) (again by distributive property)

⇒\((2x+y)\times (5x-y+3) = 10x^2-y^2+3xy+6x+3y\)  ( by operating the like terms.)

Answer:  The required product is \(10x^2-y^2+3xy+6x+3y.\)

Step-by-step explanation:  We are to find the product f the following two algebraic expressions:

\(E_1=2x+y,\\\\E_2=5x-y+3.\)

To find the product of the above two expressions, we must multiply each term of the first expression with each term of the second expression.

The multiplication is as follows:

\(M\\\\=E_1 \times E_2\\\\=(2x+y)\times(5x-y+3)\\\\=10x^2-2xy+6x+5xy-y^2+3y\\\\=10x^2-y^2+3xy+6x+3y.\)

Thus, the required product is \(10x^2-y^2+3xy+6x+3y.\)