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In the following reaction, how many liters of carbon dioxide will be produced if 250 liters of oxygen is used in the combustion of sucrose, given that both gases are at STP

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The balanced reaction would be:

C12H22O11 + 12O2 = 12CO2 + 11H2O

We are given the amount of oxygen used in the combustion. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(250 L) / (0.08206 atm L/mol K ) 273 K
n= 11.16 mol O2

11.16 mol O2 (12 mol CO2 / 12 mol O2) = 11.16 mol CO2

V = nRT/P =11.16 mol CO2 x 273 K x 0.08206 atm L/mol K / 1 atm
V=250 L

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