What is the slope of the line that passes through (3'-7)(-1'1)
To solve for slope. Remember that slope, m= (change in y)-(change in x). So that means m= (y2-y1)/(x2-x1). Putting in the values we get (1--7)=(1+7)/(-1-3)= (8)/(-4)= -2. So m, or slope is -2.
Answer:
Slope of line passing through (3,-7) and (-1,1) = -2
Step-by-step explanation:
The slope of a line passing through points (x₁,y₁) and (x₂,y₂) is given by \(\frac{y_2-y_1}{x_2-x_1}\)
Here points are given by (3,-7) and (-1,1)
So we have (x₁,y₁) = (3,-7) and (x₂,y₂) = (-1,1)
Slope \(=\frac{1-(-7)}{(-1)-3}=\frac{8}{-4} =-2\)
Slope of line passing through (3,-7) and (-1,1) = -2