Answer : The mass lost would be, \(8.71\times 10^{-10}Kg\)
Solution : Given,
Energy released = \(7.84\times 10^{7}J=7.84\times 10^{7}\text{ Kg }m^2/s^2\)
\((1J=1\text{ Kg }m^2/s^2)\)
Speed of light 'c' = \(3\times 10^{8}m/s\)
Formula used :
\(E=m\times c^2\)
where,
E = energy
m = mass
c = speed of light
Now put all the given values in the above formula, we get
\(7.84\times 10^{7}\text{ Kg }m^2/s^2=m\times (3\times 10^{8}m/s)^2\)
\(m=8.71\times 10^{-10}Kg\)
Therefore, the mass lost would be, \(8.71\times 10^{-10}Kg\)
